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View File Name :
framework.py
""" Generic framework path manipulation """ import re __all__ = ['framework_info'] STRICT_FRAMEWORK_RE = re.compile(r"""(?x) (?P<location>^.*)(?:^|/) (?P<name> (?P<shortname>\w+).framework/ (?:Versions/(?P<version>[^/]+)/)? (?P=shortname) (?:_(?P<suffix>[^_]+))? )$ """) def framework_info(filename): """ A framework name can take one of the following four forms: Location/Name.framework/Versions/SomeVersion/Name_Suffix Location/Name.framework/Versions/SomeVersion/Name Location/Name.framework/Name_Suffix Location/Name.framework/Name returns None if not found, or a mapping equivalent to: dict( location='Location', name='Name.framework/Versions/SomeVersion/Name_Suffix', shortname='Name', version='SomeVersion', suffix='Suffix', ) Note that SomeVersion and Suffix are optional and may be None if not present """ is_framework = STRICT_FRAMEWORK_RE.match(filename) if not is_framework: return None return is_framework.groupdict()